## The amount of trout y (in tons) caught in a lake from 1995 to 2014 can be modeled by the equation y = -0.08×2 + 1.6x + 10, where x is the n

Question

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## Answers ( No )

For this case, the first thing we want to do is substitute the value of y = 15 in the equation.

We have then:

15 = -0.08x ^ 2 + 1.6x + 10

Rewriting we have:

0 = -0.08x ^ 2 + 1.6x + 10 – 15

0 = -0.08x ^ 2 + 1.6x – 5

The solutions are:

x1 = 3.876275643042054

x2 = 16.123724356957947

Nearest whole number:

x1 = 4

x2 = 16

were about 15 tons of trout caught in the lake in the years:

1995 + 4 = 1999

1995 + 16 = 2011

Answer:The year 1999 and the year 2011